Discussion Forum



1)

The figure below shows currents in a part of an electric circuit. The current I is

632021665_download (3).png


A) 1.7amp

B) 3.7amp

C) 1.3amp

D) 1amp

Answer:

Option A

Explanation:

According to Kirchhoff's first law,

At junction A, iAB = 2+2 = 4A

At junction B, iAB = iBC + 1 → iBC = 4-1 = 3A

 632021154_ozzhn0gfy1bc-s.png

At junction C, i = iBC - 1.3 = 3 - 1.3 = 1.7A