1) Tube A has both ends open while tube B has one end closed, otherwise, they are identical. The ratio of the fundamental frequency of tube 'A and B' is A) 1 : 2 B) 1 : 4 C) 2 : 1 D) 4 : 1 Answer: Option CExplanation:Fundamental freq. for, Tube A = fA = $\frac{v}{2L}$ Tube B = fB = $\frac{v}{4L}$ Now, $\frac{f_{A}}{f_{B}}$ = $\frac{v}{2L} \times \frac{4L}{v}$ = $\frac{2}{1}$ = fA: fB = 2 : 1
