1)

Tube A has both ends open while tube B has one end closed, otherwise, they are identical. The ratio of the fundamental frequency of tube 'A and B' is

A) 1 : 2

B) 1 : 4

C) 2 : 1

D) 4 : 1

Option C

### Explanation:

Fundamental freq. for,

Tube A = fA = $\frac{v}{2L}$

Tube B = fB = $\frac{v}{4L}$

Now,

$\frac{f_{A}}{f_{B}}$ = $\frac{v}{2L} \times \frac{4L}{v}$

= $\frac{2}{1}$ = fA: fB = 2 : 1