1)

A man walks 1 km towards the East and then he turns to the South and walks 5 km. Again he turns to East and walks 2 km, after this, he turns to North and walks 9 km. Now, how far is he from his starting point?

A) 3 km

B) 4 km

C) 5 km

D) 7 km

Option C

Explanation:

Clearly,DF=BC=5km.

EF = (DE - DF) = (9 - 5) km = 4 km.

BF=CD=2km.

AF =AB + BF =AB + CD = (1 + 2) km = 3 km.

.'. Man's distance from starting point A

=AE = $\sqrt{AF^{2}+EF^{2}}=\sqrt{3^{2}+4^{2}}=5 km$