1) A man walks 1 km towards the East and then he turns to the South and walks 5 km. Again he turns to East and walks 2 km, after this, he turns to North and walks 9 km. Now, how far is he from his starting point? A) 3 km B) 4 km C) 5 km D) 7 km Answer: Option CExplanation: Clearly,DF=BC=5km. EF = (DE - DF) = (9 - 5) km = 4 km. BF=CD=2km. AF =AB + BF =AB + CD = (1 + 2) km = 3 km. .'. Man's distance from starting point A =AE = $\sqrt{AF^{2}+EF^{2}}=\sqrt{3^{2}+4^{2}}=5 km$
