**Answer:**

Option B

**Explanation:**

If you look into the power of 7 then you will notice a sequence:

7^{1}=7,7^{2}=49, 7^{3}=343, 7^{4}=2401, 7^{5}=16807

And the unit digits keep on repeating as { 7, 9, 3, 1 } It repeats after every 4 powers ,

So divide 95 by 4 You will get 3 as the remainder . The third number in the series is 3. **This implies the unit digit of 7**^{95} is 3 .

Similarly, do for 3^{58}

3^{1}=3, 3^{2}=9, 3^{3}=27, 3^{4}=81, 3^{5}=243 And the unit digits keep on repeating as { 3, 9, 7, 1 } Now divide 58 by 3 and get the remainder as 2 Second number in the series is 9.

**This implies unit digit of 3**^{58} is 9

Unit digit of 7^{95}−3^{58} = 3−9 = 13-9 **(**borrow from the previous digit)

**= 4**