**Answer:**

Option A

**Explanation:**

Let the total number of balls faces by D = 3x and the total number of balls faced by F = 4x.According to the question, the total number of runs made by D.

= $\frac{72\times3x}{100}$ = $\frac{216x}{100}$

The total number of runs made by F

= $\frac{66\times4x}{100}$ = $\frac{264x}{100}$

The more runs made by F as compare to D

= $\frac{264x}{100}$ - $\frac{216x}{100}$ × $\frac{48x}{100}$

So, the percentage of more runs

= $\frac{\frac{48x}{100}}{\frac{216x}{100}}\times 100-\frac{48x}{100}$ × $\frac{100}{216x}$ × 100 = $\frac{200}{9}$

= 22 $\frac{2}{9}$.