In the reaction, $C_{6}H_{5}OH\xrightarrow{NaOH}(A)$ $\xrightarrow[{140^0c,(4-7 atm)}]{CO_{2}}$

$(B)\xrightarrow{HCl}  (C)$ the compound (C) is?

A) Benzoic acid

B) Salicylaldehyde

C) Chlorobenzene

D) Salicylic acid


$A\xrightarrow[{dil.H_{2}SO_{4}}]{K_{2}Cr_{2}O_{7}}$ $B\xrightarrow[{H_{2}O}]{CH_{2}Mgl}$


the reactant A is?

A) $CH_{3}CHOHCH_{3}$

B) $CH_{3}COCH_{3}$

C) $C_{2}H_{5}OH$

D) $ CH_{3}COOH$


At low pressure, the van der Waal's equation is reduced to

A) $Z = \frac{PV_{m}}{RT} = 1-\frac{a}{VRT}$

B) $Z = \frac{PV_{m}}{RT} = 1+\frac{b}{RT}P$

C) $PV_{m} = RT$

D) $Z = \frac{PV_{m}}{RT} = 1-\frac{a}{RT}$


The volume of a closed reaction vessel in which the following equilibrium reaction occurs is halved:

$ 2SO_{2}(g) + O_{2}(g) \rightleftharpoons 2SO_{3}(g)$ As a result

A) The rates of forward and backward reactions will remain the same.

B) The equilibrium will not shift.

C) The equilibrium will shift to the right.

D) The rate of forward reaction will become double that of reverse reaction and the equilibrium will shift to the right


A coordination complex compound of cobalt has a molecular formula containing five ammonia molecules, one nitro group, and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution; on reacting with excess of AgNO3, AgCl is precipitated. The ionic formula for this complex would be:

A) $\left[Co(NH_{3})_{5}NO_{2})\right]Cl_{2}$

B) $\left[Co(NH_{3})_{5} Cl \right]\left[Cl(NO_{2})\right]$

C) $\left[Co(NH_{3})_{4}NO_{2})Cl\right] \left[(NH_{3})Cl\right]$

D) $\left[Co(NH_{3})_{5}\right]\left[(NO_{2})_{2}Cl_{2}\right]$